## CHAPTER IV.

**REPLY FROM THE OBSERVATORY OF CAMBRIDGE.**

Barbicane, however, lost not one moment amidst all the enthusiasm of which he had become the object. His first care was to reassemble his colleagues in the board-room of the Gun Club. There, after some discussion, it was agreed to consult the astronomers regarding the astronomical part of the enterprize. Their reply once ascertained, they could then discuss the mechanical means, and nothing should be wanting to ensure the success of this great experiment.

A note couched in precise terms, containing special interrogatories, was then drawn up and addressed to the Observatory of Cambridge in Massachusetts. This city, where the first University of the United States was founded, is justly celebrated for its astronomical staff. There are to be found assembled all the most eminent men of science. Here is to be seen at work that powerful telescope which enabled Bond to resolve the nebula of Andromeda, and Clarke to discover the satellite of Sirius. This celebrated institution fully justified on all points the confidence reposed in it by the Gun Club.

So, after two days, the reply so impatiently awaited was placed in the hands of President Barbicane.

It was couched in the following terms:—

“*The Director of the Cambridge Observatory to the President of the Gun Club at Baltimore.*

“CAMBRIDGE, *Oct.* 7.

“On the receipt of your favour of the 6th inst., addressed to the Observatory of Cambridge in the name of the Members of the Baltimore Gun Club, our staff was immediately called together, and it was judged expedient to reply as follows:—

“The questions which have been proposed to it are these,—

“‘1. Is it possible to transmit a projectile up to the moon?

“‘2. What is the exact distance which separates the earth from its satellite?

“‘3. What will be the period of transit of the projectile when endowed with sufficient initial velocity? and, consequently, at what moment ought it to be discharged in order that it may touch the moon at a particular point?

“‘4. At what precise moment will the moon present herself in the most favourable position to be reached by the projectile?

“‘5. What point in the heavens ought the cannon to be aimed at which is intended to discharge the projectile?

“‘6. What place will the moon occupy in the heavens at the moment of the projectile’s departure?’

“Regarding the *first* question, ‘Is it possible to transmit a projectile up to the moon?’

*“Answer*.—Yes; provided it possess an initial velocity of 1200 yards per second; calculations prove that to be sufficient. In proportion as we recede from the earth the action of gravitation diminishes in the inverse ratio of the square of the distance; that is to say, *at three times a given distance the action is nine times less.* Consequently, the weight of a shot will decrease, and will become reduced to zero at the instant that the attraction of the moon exactly counterpoises that of the earth; that is to say, at ^{47}/_{52} of its passage. At that instant the projectile will have no weight whatever; and, if it passes that point, it will fall into the moon by the sole effect of the lunar attraction. The *theoretical possibility* of the experiment is therefore absolutely demonstrated; its success must depend upon the power of the engine employed.

“As to the *second question*, ‘What is the exact distance which separates the earth from its satellite?’

*“Answer.*—The moon does not describe a circle round the earth, but rather an *ellipse*, of which our earth occupies one of the *foci;* the consequence, therefore, is, that at certain times it approaches nearer to, and at others it recedes farther from, the earth; in astronomical language, it is at one time in *apogee*, at another in *perigee.* Now the difference between its greatest and its least distance is too considerable to be left out of consideration. In point of fact, in its apogee the moon is 247,552 miles, and in its perigee, 218,657 miles only distant; a fact which makes a difference of 28,895 miles, or more than one ninth of the entire distance. The perigee distance, therefore, is that which ought to serve as the basis of all calculations.

“To the *third* question:—

*“Answer.*—If the shot should preserve continuously its initial velocity of 12,000 yards per second, it would require little more than nine hours to reach its destination; but, inasmuch as that initial velocity will be continually decreasing, it results that, taking everything into consideration, it will occupy 300,000 seconds, that is 83hrs. 20m. in reaching the point where the attraction of the earth and moon will be *in equilibrio.* From this point it will fall into the moon in 50,000 seconds, or 13hrs. 53m. 20sec. It will be desirable, therefore, to discharge it 97hrs. 13m. 20sec. before the arrival of the moon at the point aimed at.

“Regarding question *four*, ‘At what precise moment will the moon present herself in the most favourable position, &c.?’

*“Answer*.—After what has been said above, it will be necessary, first of all, to choose the period when the moon will be in perigee, and also the moment when she will be crossing the zenith, which latter event will further diminish the entire distance by a length equal to the radius of the earth, i.e. 3919 miles; the result of which will be that the final passage remaining to be accomplished will be 214,976 miles. But although the moon passes her perigee every month, she does not reach the zenith always at *exactly the same moment.* She does not appear under these two conditions simultaneously, except at long intervals of time. It will be necessary, therefore, to wait for the moment when her passage in perigee shall coincide with that in the zenith. Now, by a fortunate circumstance, on the 4th December in the ensuing year the moon *will* present these two conditions. At midnight she will be in perigee, that is, at her shortest distance from the earth, and at the same moment she will be crossing the zenith.

“On the *fifth* question, ‘At what point in the heavens ought the cannon to be aimed?’

*“Answer*.—The preceding remarks being admitted, the cannon ought to be pointed to the zenith of the place. Its fire, therefore, will be perpendicular to the plane of the horizon; and the projectile will soonest pass beyond the range of the terrestrial attraction. But, in order that the moon should reach the zenith of a given place, it is necessary that the place should not exceed in latitude the declination of the luminary; in other words, it must be comprised within the degrees 0° and 28° of lat. N. or S. In every other spot the fire must necessarily be oblique, which would seriously militate against the success of the experiment.

“As to the *sixth* question, ‘What place will the moon occupy in the heavens at the moment of the projectile’s departure?’

*“Answer*.—At the moment when the projectile shall be discharged into space, the moon, which travels daily forward 13° 10′ 35″, will be distant from the zenith point by four times that quantity, i.e. by 52° 42′ 20″, a space which corresponds to the path which she will describe during the entire journey of the projectile. But, inasmuch as it is equally necessary to take into account the deviation which the rotary motion of the earth will impart to the shot, and as the shot cannot reach the moon until after a deviation equal to 16 radii of the earth, which, calculated upon the moon’s orbit, are equal to about eleven degrees, it becomes necessary to add these eleven degrees to those which express the retardation of the moon just mentioned: that is to say, in round numbers, about 64 degrees. Consequently, at the moment of firing the visual radius applied to the moon will describe, with the vertical line of the place, an angle of sixty-four degrees.

“These are our answers to the questions proposed to the Observatory of Cambridge by the members of the Gun Club:—

“To sum up,—

“1st. The cannon ought to be planted in a country situated between between 0° and 28° of N. or S. lat.

“2ndly. It ought to be pointed directly towards the zenith of the place.

“3rdly. The projectile ought to be propelled with an initial velocity of 12,000 yards per second.

“4thly. It ought to be discharged at 10hrs. 46m. 40sec. of the 1st December of the ensuing year.

“5thly. It will meet the moon four days after its discharge, precisely at midnight on the 4th December, at the moment of its transit across the zenith.

“The members of the Gun Club ought, therefore, without delay, to commence the works necessary for such an experiment, and to be prepared to set to work at the moment determined upon; for, if they should suffer this 4th December to go by, they will not find the moon again under the same conditions of perigee and of zenith until eighteen years and eleven days afterwards.

“The Staff of the Cambridge Observatory place themselves entirely at their disposal in respect of all questions of theoretical astronomy; and herewith add their congratulations to those of all the rest of America.

“For the Astronomical Staff,

“J. M. BELFAST,

“*Director of the Observatory of Cambridge.*“